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| 1 | +// Java Program to Implement Strassen Algorithm |
| 2 | + |
| 3 | +// Class Strassen matrix multiplication |
| 4 | +public class StrassenMatrixMultiplication { |
| 5 | + |
| 6 | + // Method 1 |
| 7 | + // Function to multiply matrices |
| 8 | + public int[][] multiply(int[][] A, int[][] B) |
| 9 | + { |
| 10 | + int n = A.length; |
| 11 | + |
| 12 | + int[][] R = new int[n][n]; |
| 13 | + |
| 14 | + if (n == 1) |
| 15 | + |
| 16 | + R[0][0] = A[0][0] * B[0][0]; |
| 17 | + |
| 18 | + else { |
| 19 | + // Dividing Matrix into parts |
| 20 | + // by storing sub-parts to variables |
| 21 | + int[][] A11 = new int[n / 2][n / 2]; |
| 22 | + int[][] A12 = new int[n / 2][n / 2]; |
| 23 | + int[][] A21 = new int[n / 2][n / 2]; |
| 24 | + int[][] A22 = new int[n / 2][n / 2]; |
| 25 | + int[][] B11 = new int[n / 2][n / 2]; |
| 26 | + int[][] B12 = new int[n / 2][n / 2]; |
| 27 | + int[][] B21 = new int[n / 2][n / 2]; |
| 28 | + int[][] B22 = new int[n / 2][n / 2]; |
| 29 | + |
| 30 | + // Dividing matrix A into 4 parts |
| 31 | + split(A, A11, 0, 0); |
| 32 | + split(A, A12, 0, n / 2); |
| 33 | + split(A, A21, n / 2, 0); |
| 34 | + split(A, A22, n / 2, n / 2); |
| 35 | + |
| 36 | + // Dividing matrix B into 4 parts |
| 37 | + split(B, B11, 0, 0); |
| 38 | + split(B, B12, 0, n / 2); |
| 39 | + split(B, B21, n / 2, 0); |
| 40 | + split(B, B22, n / 2, n / 2); |
| 41 | + |
| 42 | + // Using Formulas as described in algorithm |
| 43 | + |
| 44 | + // M1:=(A1+A3)×(B1+B2) |
| 45 | + int[][] M1 |
| 46 | + = multiply(add(A11, A22), add(B11, B22)); |
| 47 | + |
| 48 | + // M2:=(A2+A4)×(B3+B4) |
| 49 | + int[][] M2 = multiply(add(A21, A22), B11); |
| 50 | + |
| 51 | + // M3:=(A1−A4)×(B1+A4) |
| 52 | + int[][] M3 = multiply(A11, sub(B12, B22)); |
| 53 | + |
| 54 | + // M4:=A1×(B2−B4) |
| 55 | + int[][] M4 = multiply(A22, sub(B21, B11)); |
| 56 | + |
| 57 | + // M5:=(A3+A4)×(B1) |
| 58 | + int[][] M5 = multiply(add(A11, A12), B22); |
| 59 | + |
| 60 | + // M6:=(A1+A2)×(B4) |
| 61 | + int[][] M6 |
| 62 | + = multiply(sub(A21, A11), add(B11, B12)); |
| 63 | + |
| 64 | + // M7:=A4×(B3−B1) |
| 65 | + int[][] M7 |
| 66 | + = multiply(sub(A12, A22), add(B21, B22)); |
| 67 | + |
| 68 | + // P:=M2+M3−M6−M7 |
| 69 | + int[][] C11 = add(sub(add(M1, M4), M5), M7); |
| 70 | + |
| 71 | + // Q:=M4+M6 |
| 72 | + int[][] C12 = add(M3, M5); |
| 73 | + |
| 74 | + // R:=M5+M7 |
| 75 | + int[][] C21 = add(M2, M4); |
| 76 | + |
| 77 | + // S:=M1−M3−M4−M5 |
| 78 | + int[][] C22 = add(sub(add(M1, M3), M2), M6); |
| 79 | + |
| 80 | + join(C11, R, 0, 0); |
| 81 | + join(C12, R, 0, n / 2); |
| 82 | + join(C21, R, n / 2, 0); |
| 83 | + join(C22, R, n / 2, n / 2); |
| 84 | + } |
| 85 | + |
| 86 | + return R; |
| 87 | + } |
| 88 | + |
| 89 | + // Method 2 |
| 90 | + // Function to subtract two matrices |
| 91 | + public int[][] sub(int[][] A, int[][] B) |
| 92 | + { |
| 93 | + int n = A.length; |
| 94 | + |
| 95 | + int[][] C = new int[n][n]; |
| 96 | + |
| 97 | + for (int i = 0; i < n; i++) |
| 98 | + for (int j = 0; j < n; j++) |
| 99 | + C[i][j] = A[i][j] - B[i][j]; |
| 100 | + |
| 101 | + return C; |
| 102 | + } |
| 103 | + |
| 104 | + // Method 3 |
| 105 | + // Function to add two matrices |
| 106 | + public int[][] add(int[][] A, int[][] B) |
| 107 | + { |
| 108 | + |
| 109 | + int n = A.length; |
| 110 | + |
| 111 | + int[][] C = new int[n][n]; |
| 112 | + |
| 113 | + for (int i = 0; i < n; i++) |
| 114 | + for (int j = 0; j < n; j++) |
| 115 | + C[i][j] = A[i][j] + B[i][j]; |
| 116 | + |
| 117 | + return C; |
| 118 | + } |
| 119 | + |
| 120 | + // Method 4 |
| 121 | + // Function to split parent matrix |
| 122 | + // into child matrices |
| 123 | + public void split(int[][] P, int[][] C, int iB, int jB) |
| 124 | + { |
| 125 | + for (int i1 = 0, i2 = iB; i1 < C.length; i1++, i2++) |
| 126 | + for (int j1 = 0, j2 = jB; j1 < C.length; j1++, j2++) |
| 127 | + C[i1][j1] = P[i2][j2]; |
| 128 | + } |
| 129 | + |
| 130 | + // Method 5 |
| 131 | + // Function to join child matrices |
| 132 | + // into (to) parent matrix |
| 133 | + public void join(int[][] C, int[][] P, int iB, int jB) |
| 134 | + |
| 135 | + { |
| 136 | + for (int i1 = 0, i2 = iB; i1 < C.length; i1++, i2++) |
| 137 | + for (int j1 = 0, j2 = jB; j1 < C.length; j1++, j2++) |
| 138 | + P[i2][j2] = C[i1][j1]; |
| 139 | + } |
| 140 | + |
| 141 | + // Method 5 |
| 142 | + // Main driver method |
| 143 | + public static void main(String[] args) |
| 144 | + { |
| 145 | + System.out.println("Strassen Multiplication Algorithm Implementation For Matrix Multiplication :\n"); |
| 146 | + |
| 147 | + StrassenMatrixMultiplication s = new StrassenMatrixMultiplication(); |
| 148 | + |
| 149 | + // Size of matrix |
| 150 | + // Considering size as 4 in order to illustrate |
| 151 | + int N = 4; |
| 152 | + |
| 153 | + // Matrix A |
| 154 | + // Custom input to matrix |
| 155 | + int[][] A = { { 1, 2, 5, 4 }, |
| 156 | + { 9, 3, 0, 6 }, |
| 157 | + { 4, 6, 3, 1 }, |
| 158 | + { 0, 2, 0, 6 } }; |
| 159 | + |
| 160 | + // Matrix B |
| 161 | + // Custom input to matrix |
| 162 | + int[][] B = { { 1, 0, 4, 1 }, |
| 163 | + { 1, 2, 0, 2 }, |
| 164 | + { 0, 3, 1, 3 }, |
| 165 | + { 1, 8, 1, 2 } }; |
| 166 | + |
| 167 | + // Matrix C computations |
| 168 | + |
| 169 | + // Matrix C calling method to get Result |
| 170 | + int[][] C = s.multiply(A, B); |
| 171 | + |
| 172 | + System.out.println("\nProduct of matrices A and B : "); |
| 173 | + |
| 174 | + // Print the output |
| 175 | + for (int i = 0; i < N; i++) { |
| 176 | + for (int j = 0; j < N; j++) |
| 177 | + System.out.print(C[i][j] + " "); |
| 178 | + System.out.println(); |
| 179 | + } |
| 180 | + } |
| 181 | +} |
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