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Wrong binding of closure variable with intervening list comprehension #121377
Description
Bug report
Bug description:
def f(x):
def g():
print([x for x in range(10)])
def h():
print(x)
return h
print(x)
return g
f(1)()()The above had always bound x in h to the parameter of f. But it no longer works and somehow binds to a local in g, throwing the following error:
NameError: cannot access free variable 'x' where it is not associated with a value in enclosing scope
CPython versions tested on:
3.12
Operating systems tested on:
Linux, Windows
Activity
gaogaotiantian commentedon Jul 4, 2024
This is probably related to PEP 709 @carljm .
carljm commentedon Jul 5, 2024
I've just moved house and am behind on everything, so it may be a bit before I can get to this, but I will fix it.
limwz01 commentedon Aug 27, 2024
@carljm any updates?
carljm commentedon Aug 27, 2024
I'm intending to work on this during the upcoming core dev sprint in September. If someone else gets to it first that's fine, though!
pythongh-121377: Fix closure with intervening comprehension
pythongh-121377: Fix closure with intervening comprehension