Fix 'infer T' type parameter leaks#22959
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Can we have a test that infers from a type parameter with an explicit constraint? function foo2<T extends string[]>(x: T extends (infer U)[] ? U[] : never) {
let e = x[0];
} |
mhegazy
approved these changes
Mar 28, 2018
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With this PR we properly erase 'infer T' type parameters to their constraints when producing the base constraint of a conditional type. For example:
Previously the
Utype parameter would leak and become the type ofe.