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code_6_5.cpp
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42 lines (36 loc) · 1.05 KB
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#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
int main() {
// 入力
int N;
cin >> N;
vector<long long> H(N), S(N);
for (int i = 0; i < N; i++) cin >> H[i] >> S[i];
// 二分探索の上限値を求める
long long M = 0;
for (int i = 0; i < N; ++i) M = max(M, H[i] + S[i] * N);
// 二分探索
long long left = 0, right = M;
while (right - left > 1) {
long long mid = (left + right) / 2;
// 判定する
bool ok = true;
vector<long long> t(N, 0); // 各風船を割るまでの制限時間
for (int i = 0; i < N; ++i) {
// そもそも mid が初期高度より低かったら false
if (mid < H[i]) ok = false;
else t[i] = (mid - H[i]) / S[i];
}
// 時間制限がさし迫っている順にソート する
sort(t.begin(), t.end());
for (int i = 0; i < N; ++i) {
// 時間切れ発生の場合は false
if (t[i] < i) ok = false;
}
if (ok) right = mid;
else left = mid;
}
cout << right << endl;
}