create sum_of_digits.py#2065
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create sum_of_digits.py to find the sum of digits of a number digit_sum(12345) ---> 15 digit_sum(12345) ---> 10
cclauss
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Jun 2, 2020
| """ | ||
| res = 0 | ||
| while n > 0: | ||
| res += n % 10 |
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Could we optimize using Python builtin https://docs.python.org/3/library/functions.html#divmod ?
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Yeah, divmod() method would be faster than mod operator. But for small values, there is not much difference. Everytime, we mod a number with 10 until it becomes 0 will not have much effect on the running time I guess.
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def digits(n):
while n:
n, digit = divmod(n, 10)
yield digit
print(sum(digits(12345)))
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Yeah, that's the digit sum function using divmod()
Co-authored-by: Christian Clauss <cclauss@me.com>
Co-authored-by: Christian Clauss <cclauss@me.com>
cclauss
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Jun 2, 2020
stokhos
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Jan 3, 2021
* create sum_of_digits.py create sum_of_digits.py to find the sum of digits of a number digit_sum(12345) ---> 15 digit_sum(12345) ---> 10 * Update sum_of_digits.py * Update maths/sum_of_digits.py Co-authored-by: Christian Clauss <cclauss@me.com> * Update maths/sum_of_digits.py Co-authored-by: Christian Clauss <cclauss@me.com> * Update sum_of_digits.py Co-authored-by: Christian Clauss <cclauss@me.com>
GlennCheng
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Apr 20, 2026
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create sum_of_digits.py to find the sum of digits of a number
digit_sum(12345) ---> 15
digit_sum(1234) ---> 10