# Spiral Print

# ------------------------

# Given an N*M 2D array, print it in spiral form. That is, first you need to print the 1st row, then last column, then last row and then first column and so on.

# Print every element only once.

# Input format :

# Line 1 : N and M, No. of rows & No. of columns (separated by space) followed by N*M elements in row wise fashion.

# Output format :

# Elements of matrix in spiral form in a single line and space separated

# Constraints :

# 0 <= N <= 10^4

# 0 <= M <= 10^4

# Sample Input 1:

# 4 4 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

# Sample Output 1:

# 1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10

def spiralPrint(arr):

rows = len(arr)

cols = len(arr[0])

startRow, startCol, endRow, endCol = 0, 0, rows-1, cols-1

while startRow<=endRow and startCol<=endCol:

# Print startRow

for j in range(startCol, endCol+1):

print(arr[startRow][j], end=' ')

startRow += 1

if startRow>endRow or startCol>endCol:

break

# Print endCol

for i in range(startRow, endRow+1):

print(arr[i][endCol], end=' ')

endCol -= 1

if startRow>endRow or startCol>endCol:

break

for j in range(endCol, startCol-1, -1):

print(arr[endRow][j], end=' ')

endRow -= 1

if startRow>endRow or startCol>endCol:

break

# Print startCol

for i in range(endRow, startRow-1, -1):

print(arr[i][startCol], end=' ')

startCol += 1

l=[int(i) for i in input().strip().split(' ')]

m, n=l[0], l[1]

arr = [ [ l[(j*n)+i+2] for i in range(n)] for j in range(m)]

spiralPrint(arr)