def top1(lst):
    return max(lst, default='列表为空', key=lambda v: lst.count(v))

lst = [1, 3, 3, 2, 1, 1, 2]
r = top1(lst)
print(f'{lst}中出现次数最多的元素为:{r}')  # [1, 3, 3, 2, 1, 1, 2]中出现次数最多的元素为:1