解决多表join，生成的sql未按join参数顺序，乱序问题

zhoulingfengofcd · zhoulingfengofcd · commit 54b6690e6471 · 2020-03-05T23:21:49.000+08:00
diff --git a/APIJSON-Java-Server/APIJSONORM/src/main/java/apijson/server/AbstractParser.java b/APIJSON-Java-Server/APIJSONORM/src/main/java/apijson/server/AbstractParser.java
@@ -937,7 +937,7 @@ private List<Join> onJoinParse(Object join, JSONObject request) throws Exception
 		else if (join instanceof String) {
 			String[] sArr = request == null || request.isEmpty() ? null : StringUtil.split((String) join);
 			if (sArr != null && sArr.length > 0) {
-				joinMap = new JSONObject();
+				joinMap = new JSONObject(true); //注意：这里必须要保证join连接顺序，保证后边遍历是按照join参数的顺序生成的SQL
 				for (int i = 0; i < sArr.length; i++) {
 					joinMap.put(sArr[i], new JSONObject());
 				}

Original file line number	Diff line number	Diff line change
`@@ -937,7 +937,7 @@ private List<Join> onJoinParse(Object join, JSONObject request) throws Exception`
`937`	`937`	`else if (join instanceof String) {`
`938`	`938`	`String[] sArr = request == null \|\| request.isEmpty() ? null : StringUtil.split((String) join);`
`939`	`939`	`if (sArr != null && sArr.length > 0) {`
`940`		`- joinMap = new JSONObject();`
	`940`	`+ joinMap = new JSONObject(true); //注意：这里必须要保证join连接顺序，保证后边遍历是按照join参数的顺序生成的SQL`
`941`	`941`	`for (int i = 0; i < sArr.length; i++) {`
`942`	`942`	`joinMap.put(sArr[i], new JSONObject());`
`943`	`943`	`}`