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| 1 | + |
| 2 | +# Python program to solve N Queen |
| 3 | +# Problem using backtracking |
| 4 | + |
| 5 | + |
| 6 | + |
| 7 | +global N |
| 8 | + |
| 9 | +N = 4 |
| 10 | + |
| 11 | + |
| 12 | + |
| 13 | +def printSolution(board): |
| 14 | + |
| 15 | + for i in range(N): |
| 16 | + |
| 17 | + for j in range(N): |
| 18 | + |
| 19 | + print board[i][j], |
| 20 | + |
| 21 | + print |
| 22 | + |
| 23 | + |
| 24 | + |
| 25 | + |
| 26 | +# A utility function to check if a queen can |
| 27 | +# be placed on board[row][col]. Note that this |
| 28 | +# function is called when "col" queens are |
| 29 | +# already placed in columns from 0 to col -1. |
| 30 | +# So we need to check only left side for |
| 31 | +# attacking queens |
| 32 | + |
| 33 | +def isSafe(board, row, col): |
| 34 | + |
| 35 | + |
| 36 | + |
| 37 | + # Check this row on left side |
| 38 | + |
| 39 | + for i in range(col): |
| 40 | + |
| 41 | + if board[row][i] == 1: |
| 42 | + |
| 43 | + return False |
| 44 | + |
| 45 | + |
| 46 | + |
| 47 | + # Check upper diagonal on left side |
| 48 | + |
| 49 | + for i, j in zip(range(row, -1, -1), range(col, -1, -1)): |
| 50 | + |
| 51 | + if board[i][j] == 1: |
| 52 | + |
| 53 | + return False |
| 54 | + |
| 55 | + |
| 56 | + |
| 57 | + # Check lower diagonal on left side |
| 58 | + |
| 59 | + for i, j in zip(range(row, N, 1), range(col, -1, -1)): |
| 60 | + |
| 61 | + if board[i][j] == 1: |
| 62 | + |
| 63 | + return False |
| 64 | + |
| 65 | + |
| 66 | + |
| 67 | + return True |
| 68 | + |
| 69 | + |
| 70 | + |
| 71 | +def solveNQUtil(board, col): |
| 72 | + |
| 73 | + # base case: If all queens are placed |
| 74 | + |
| 75 | + # then return true |
| 76 | + |
| 77 | + if col >= N: |
| 78 | + |
| 79 | + return True |
| 80 | + |
| 81 | + |
| 82 | + |
| 83 | + # Consider this column and try placing |
| 84 | + |
| 85 | + # this queen in all rows one by one |
| 86 | + |
| 87 | + for i in range(N): |
| 88 | + |
| 89 | + |
| 90 | + |
| 91 | + if isSafe(board, i, col): |
| 92 | + |
| 93 | + # Place this queen in board[i][col] |
| 94 | + |
| 95 | + board[i][col] = 1 |
| 96 | + |
| 97 | + |
| 98 | + |
| 99 | + # recur to place rest of the queens |
| 100 | + |
| 101 | + if solveNQUtil(board, col + 1) == True: |
| 102 | + |
| 103 | + return True |
| 104 | + |
| 105 | + |
| 106 | + |
| 107 | + # If placing queen in board[i][col |
| 108 | + |
| 109 | + # doesn't lead to a solution, then |
| 110 | + |
| 111 | + # queen from board[i][col] |
| 112 | + |
| 113 | + board[i][col] = 0 |
| 114 | + |
| 115 | + |
| 116 | + |
| 117 | + # if the queen can not be placed in any row in |
| 118 | + |
| 119 | + # this colum col then return false |
| 120 | + |
| 121 | + return False |
| 122 | + |
| 123 | + |
| 124 | +# This function solves the N Queen problem using |
| 125 | +# Backtracking. It mainly uses solveNQUtil() to |
| 126 | +# solve the problem. It returns false if queens |
| 127 | +# cannot be placed, otherwise return true and |
| 128 | +# placement of queens in the form of 1s. |
| 129 | +# note that there may be more than one |
| 130 | +# solutions, this function prints one of the |
| 131 | +# feasible solutions. |
| 132 | + |
| 133 | +def solveNQ(): |
| 134 | + |
| 135 | + board = [ [0, 0, 0, 0], |
| 136 | + |
| 137 | + [0, 0, 0, 0], |
| 138 | + |
| 139 | + [0, 0, 0, 0], |
| 140 | + |
| 141 | + [0, 0, 0, 0] |
| 142 | + |
| 143 | + ] |
| 144 | + |
| 145 | + |
| 146 | + |
| 147 | + if solveNQUtil(board, 0) == False: |
| 148 | + |
| 149 | + print "Solution does not exist" |
| 150 | + |
| 151 | + return False |
| 152 | + |
| 153 | + |
| 154 | + |
| 155 | + printSolution(board) |
| 156 | + |
| 157 | + return True |
| 158 | + |
| 159 | + |
| 160 | +# driver program to test above function |
| 161 | +solveNQ() |
| 162 | + |
| 163 | + |
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