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| 1 | +package algorithm; |
| 2 | + |
| 3 | +import org.junit.Test; |
| 4 | + |
| 5 | +import java.util.HashMap; |
| 6 | +import java.util.Map; |
| 7 | + |
| 8 | +import static org.hamcrest.CoreMatchers.is; |
| 9 | +import static org.junit.Assert.assertThat; |
| 10 | + |
| 11 | +public class IsAnagram { |
| 12 | + |
| 13 | + /* |
| 14 | + TASK |
| 15 | + 주어진 문자열이 애너그램인지를 판단한다. |
| 16 | + */ |
| 17 | + |
| 18 | + // 방법 1. O(nlogn) : 정렬 후에 비교하기 |
| 19 | + // 방법 2. O(n) : 문자열 개수를 세서 비교하기 |
| 20 | + |
| 21 | + @Test |
| 22 | + public void 애너그램판별하기() { |
| 23 | + assertThat(true, is(애너그램판별_USE_MAP("arc", "car"))); |
| 24 | + assertThat(true, is(애너그램판별_USE_MAP("caaabbb", "abababc"))); |
| 25 | + assertThat(false, is(애너그램판별_USE_MAP("caabbbb", "abababc"))); |
| 26 | + assertThat(false, is(애너그램판별_USE_MAP("arc", "carr"))); |
| 27 | + assertThat(false, is(애너그램판별_USE_MAP("arc", "caz"))); |
| 28 | + } |
| 29 | + |
| 30 | + private boolean 애너그램판별_USE_MAP(String str1, String str2) { |
| 31 | + if (str1.length() != str2.length()) return false; |
| 32 | + |
| 33 | + Map<Character, Integer> strMap = new HashMap<Character, Integer>(); |
| 34 | + |
| 35 | + for (char c : str1.toCharArray()) { |
| 36 | + if (strMap.containsKey(c)) { |
| 37 | + strMap.put(c, strMap.get(c) + 1); |
| 38 | + } else { |
| 39 | + strMap.put(c, 1); |
| 40 | + } |
| 41 | + } |
| 42 | + |
| 43 | + for (char c : str2.toCharArray()) { |
| 44 | + if (!strMap.containsKey(c)) { |
| 45 | + return false; |
| 46 | + } |
| 47 | + if (strMap.get(c) == 0) { |
| 48 | + return false; |
| 49 | + } |
| 50 | + strMap.put(c, strMap.get(c) - 1); |
| 51 | + } |
| 52 | + |
| 53 | + return true; |
| 54 | + } |
| 55 | +} |
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