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iter.po
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45 lines (40 loc) · 1.38 KB
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# SOME DESCRIPTIVE TITLE.
# Copyright (C) 2001-2018, Python Software Foundation
# This file is distributed under the same license as the Python package.
#
# Translators:
msgid ""
msgstr ""
"Project-Id-Version: Python 3.7\n"
"Report-Msgid-Bugs-To: \n"
"POT-Creation-Date: 2020-06-20 18:04+0800\n"
"PO-Revision-Date: 2015-12-09 17:51+0000\n"
"Last-Translator: Liang-Bo Wang <me@liang2.tw>\n"
"Language-Team: Chinese - TAIWAN (https://github.com/python/python-docs-zh-"
"tw)\n"
"Language: zh_TW\n"
"MIME-Version: 1.0\n"
"Content-Type: text/plain; charset=UTF-8\n"
"Content-Transfer-Encoding: 8bit\n"
"Plural-Forms: nplurals=1; plural=0;\n"
#: ../../c-api/iter.rst:6
msgid "Iterator Protocol"
msgstr ""
#: ../../c-api/iter.rst:8
msgid "There are two functions specifically for working with iterators."
msgstr ""
#: ../../c-api/iter.rst:12
msgid "Return true if the object *o* supports the iterator protocol."
msgstr ""
#: ../../c-api/iter.rst:17
msgid ""
"Return the next value from the iteration *o*. The object must be an "
"iterator (it is up to the caller to check this). If there are no remaining "
"values, returns ``NULL`` with no exception set. If an error occurs while "
"retrieving the item, returns ``NULL`` and passes along the exception."
msgstr ""
#: ../../c-api/iter.rst:22
msgid ""
"To write a loop which iterates over an iterator, the C code should look "
"something like this::"
msgstr ""