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d_Merge.java
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package Algorithms_4thEdition.a_Sorting;
import Standard.stdOut;
import Standard.stdRandom;
/**
* Created by nibnait on 2016/8/8.
*/
public class d_Merge {
public static void main(String[] args) {
int[] a = new int[7];
a = stdRandom.random(a);
stdOut.print(a);
a = Merge_Sort(a, 0, a.length-1);
stdOut.print(a);
}
/**
* 时间复杂度:N*lgN
* 但是 需要辅助数组。
*/
// private static int[] aux = new int[100]; //避免时间都浪费到 创建数组上。
public static int[] Merge_Sort(int[] a, int lo, int hi) {
if (lo>=hi){ //lo > == hi 的时候,就说明 不能再分了,可以开始归并了
return a;
}
int mid = (lo+hi)/2;
int N = a.length;
//递归的将数组分到不能再分
Merge_Sort(a, lo, mid);
Merge_Sort(a, mid+1, hi);
//开始Merge
Merge(a, lo, mid, hi);
return a;
}
/*private static void Sort(int[] a, int lo, int hi) {
if (lo>=hi){ //lo > == hi 的时候,就说明 不能再分了,可以开始归并了
return;
}
int mid = (lo+hi)/2;
Sort(a, lo, mid);
Sort(a, mid+1, hi);
//开始Merge
Merge(a, lo, mid, hi);
}*/
private static void Merge(int[] a, int lo, int mid, int hi) {
//新建一个辅助数组
int aux[] = new int[a.length+1];
for (int i = lo; i <= hi; i++) {
aux[i] = a[i];
}
//开始合并!
int i = lo, j = mid+1;
for (int k = lo; k <= hi; k++) {
if ((aux[i]<=aux[j] && i<=mid) || j>hi){
a[k] = aux[i++];
}else {
a[k] = aux[j++];
}
}
}
}