package two_pointers; import java.util.ArrayList; import java.util.Arrays; import java.util.List; /** * Created by gouthamvidyapradhan on 29/03/2017. Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target. Note: The solution set must not contain duplicate quadruplets. For example, given array S = [1, 0, -1, 0, -2, 2], and target = 0. A solution set is: [ [-1, 0, 0, 1], [-2, -1, 1, 2], [-2, 0, 0, 2] ] */ public class FourSum { /** * Main method * @param args * @throws Exception */ public static void main(String[] args) throws Exception { int[] nums = {1, 0, -1, 0, -2, 2}; System.out.println(new FourSum().fourSum(nums, 0)); } public List> fourSum(int[] nums, int target) { List> result = new ArrayList<>(); if(nums.length < 4) return result; Arrays.sort(nums); for(int i = 0; i < nums.length - 3; i++) { if(i == 0 || nums[i] != nums[i - 1]) { for(int j = i + 1; j < nums.length - 2; j ++) { if(j == i + 1 || nums[j] != nums[j - 1]) { int k = j + 1, l = nums.length - 1; while(k < l) { if(k != j + 1 && nums[k] == nums[k + 1]) { k++; continue; } int sum = nums[i] + nums[j] + nums[k] + nums[l]; if(sum == target) { result.add(Arrays.asList(nums[i], nums[j], nums[k], nums[l])); k++; l --; } else if(sum < target) { k ++; } else { l --; } } } } } } return result; } }