From c7202facab0d684663893fd987246922cb642ae7 Mon Sep 17 00:00:00 2001
From: Damaris Goebel <damaris.goebel@gmx.de>
Date: Fri, 6 Mar 2020 14:28:27 +0100
Subject: [PATCH] voila

---
 js/index.js | 50 +++++++++++++++++++++++++++++++++++++++++++++++++-
 1 file changed, 49 insertions(+), 1 deletion(-)

diff --git a/js/index.js b/js/index.js
index dd8ff0062..71383e96a 100644
--- a/js/index.js
+++ b/js/index.js
@@ -1,7 +1,55 @@
 // Iteration 1: Names and Input
+let hacker1 = 'Damaris'
+console.log(`The driver's name is ${hacker1}.`)
 
+let hacker2 = 'Damaris'
+console.log(`The navigator's name is ${hacker2}.`)
 
 // Iteration 2: Conditionals
 
+if (hacker1.length > hacker2.length){
+    console.log(`The driver has the longest name, it has ${hacker1.length} characters.`)
+} else if (hacker2.length > hacker1.length) {
+    console.log (`It seems that the navigator has the longest name, it has ${hacker2.length} characters.`)
+} else {
+    console.log(`Wow, you both have equally long names, ${hacker1.length} characters!`)
+}
 
-// Iteration 3: Loops
\ No newline at end of file
+
+// Iteration 3: Loops
+
+
+console.log(hacker1.split('').join(' ').toUpperCase())
+
+
+    // let space = ' ';
+    // for(let i=0; i<hacker1.length; i++){
+    //     space += i + ' '; 
+    //     console.log(space.trim())    
+    //  }
+        
+
+function reverseString(str) {
+    return str.split("").reverse().join("");
+}
+reverseString(hacker2);
+
+
+// 3.3 Depending on the lexicographic order of the strings, print:
+// - The driver's name goes first.
+// - Yo, the navigator goes first definitely.
+// - What?! You both have the same name?
+
+function lexicheck (a, b) {
+    if(a === b) {
+        console.log('What?! You both have the same name?');
+    }
+
+     else if (a < b) {
+        console.log(`The driver's name goes first`);
+    } else if (a > b) {
+        console.log('Yo, the navigator goes first definitely.')
+    }
+}
+
+lexicheck(hacker1,hacker2)
\ No newline at end of file