From a265bd75da4fa21587853e8fc130643082da0571 Mon Sep 17 00:00:00 2001
From: Gooss <gooss@media-saturn.com>
Date: Mon, 18 Nov 2019 16:33:24 +0100
Subject: [PATCH 1/4] First push

---
 JS-Basic-Javascript.js | 0
 1 file changed, 0 insertions(+), 0 deletions(-)
 create mode 100644 JS-Basic-Javascript.js

diff --git a/JS-Basic-Javascript.js b/JS-Basic-Javascript.js
new file mode 100644
index 000000000..e69de29bb

From 8c32f5726def7cd13617fc554d5d4f4693fb22b2 Mon Sep 17 00:00:00 2001
From: Gooss <gooss@media-saturn.com>
Date: Mon, 18 Nov 2019 16:50:41 +0100
Subject: [PATCH 2/4] First iteration done

---
 JS-Basic-Javascript.js |  0
 index.js               | 34 ++++++++++++++++++++++++++++++++++
 2 files changed, 34 insertions(+)
 delete mode 100644 JS-Basic-Javascript.js
 create mode 100644 index.js

diff --git a/JS-Basic-Javascript.js b/JS-Basic-Javascript.js
deleted file mode 100644
index e69de29bb..000000000
diff --git a/index.js b/index.js
new file mode 100644
index 000000000..4258ecf29
--- /dev/null
+++ b/index.js
@@ -0,0 +1,34 @@
+/*Iteration 1: Names and Input
+1.1 Create a variable hacker1 with the driver's name.*/
+let hacker1 = "Juergen";
+
+
+//1.2 Print "The driver's name is XXXX".//
+
+console.log(`The driver´s name is ${hacker1}`);
+
+//1.3 Create a variable hacker2 with the navigator's name.//
+
+let hacker2 = "Alina";
+let hacker3 = "Sergej";
+
+//1.4 Print "The navigator's name is YYYY".//
+
+console.log(`The navigators are ${hacker2}, ${hacker3}`);
+
+/*Iteration 2: Conditionals
+2.1. Depending on which name is longer, print: - The Driver has the longest name, it has XX characters or - Yo, navigator got the longest name, it has XX characters or - Wow, you both got equally long names, XX characters!*/
+
+/*Iteration 3: Loops
+3.1 Print all the characters of the driver's name, separated by a space and in capitals i.e. "J O H N"*/
+
+//3.2 Print all the characters of the navigator's name, in reverse order. i.e. "nhoJ"//
+
+//3.3 Depending on the lexicographic order of the strings, print: - The driver's name goes first. - Yo, the navigator goes first definitely. - What?! You both got the same name?//
+
+/*Bonus Time!
+Go to lorem ipsum generator and:
+
+Generate 3 paragraphs. Store the text in a variable type of string.
+Make your program count the number of words in the string.
+Make your program count the number of times the Latin word et appears.*/
\ No newline at end of file

From f67e129703003aef07e5dd0827db92118fbba765 Mon Sep 17 00:00:00 2001
From: Gooss <gooss@media-saturn.com>
Date: Mon, 18 Nov 2019 17:19:41 +0100
Subject: [PATCH 3/4] Second iteration done

---
 index.js | 15 ++++++++++++---
 1 file changed, 12 insertions(+), 3 deletions(-)

diff --git a/index.js b/index.js
index 4258ecf29..80414431d 100644
--- a/index.js
+++ b/index.js
@@ -9,16 +9,25 @@ console.log(`The driver´s name is ${hacker1}`);
 
 //1.3 Create a variable hacker2 with the navigator's name.//
 
-let hacker2 = "Alina";
-let hacker3 = "Sergej";
+let hacker2 = "AlinaSergej";
 
 //1.4 Print "The navigator's name is YYYY".//
 
-console.log(`The navigators are ${hacker2}, ${hacker3}`);
+console.log(`The navigator´s name is ${hacker2}`);
 
 /*Iteration 2: Conditionals
 2.1. Depending on which name is longer, print: - The Driver has the longest name, it has XX characters or - Yo, navigator got the longest name, it has XX characters or - Wow, you both got equally long names, XX characters!*/
 
+if (hacker1.length >=hacker2.length){
+  if (hacker1.length == hacker2.length){
+    console.log(`Wow, you both got equally long names, ${hacker1.length} characters!`)
+  } else {
+    console.log(`The Driver has the longest name, it has ${hacker1.length} characters`)
+  } 
+} else {
+  console.log(`Yo, navigator got the longest name, it has ${hacker2.length} characters`)
+}
+
 /*Iteration 3: Loops
 3.1 Print all the characters of the driver's name, separated by a space and in capitals i.e. "J O H N"*/
 

From f05ded3785ee9c5c34bdc94eb432ae47fa8196f2 Mon Sep 17 00:00:00 2001
From: Gooss <gooss@media-saturn.com>
Date: Mon, 18 Nov 2019 18:08:16 +0100
Subject: [PATCH 4/4] Third iteration done

---
 index.js | 73 ++++++++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 73 insertions(+)

diff --git a/index.js b/index.js
index 80414431d..bf61179ba 100644
--- a/index.js
+++ b/index.js
@@ -3,6 +3,18 @@
 let hacker1 = "Juergen";
 
 
+//1.2 Print "The driver's name is XXXX".//
+
+console.log(`The driver´s name is ${hacker1}`);
+
+//1.3 Create a variable hacker2 with the navigator's name.//
+
+let hacker2 = "AlinaSergej";
+/*Iteration 1: Names and Input
+1.1 Create a variable hacker1 with the driver's name.*/
+let hacker1 = "Juergen";
+
+
 //1.2 Print "The driver's name is XXXX".//
 
 console.log(`The driver´s name is ${hacker1}`);
@@ -31,6 +43,67 @@ if (hacker1.length >=hacker2.length){
 /*Iteration 3: Loops
 3.1 Print all the characters of the driver's name, separated by a space and in capitals i.e. "J O H N"*/
 
+let uppercasedDriver=hacker1.toUpperCase();
+/*let split="";
+. Solution:
+for (let i = 0; i<hacker1.length; i++){
+   split += `${uppercasedDriver[i]}  `;
+  
+}
+console.log(split);*/
+
+let splittedName = uppercasedDriver.split("");
+let nameFinal = splittedName.join(" ")
+console.log(nameFinal)
+
+//3.2 Print all the characters of the navigator's name, in reverse order. i.e. "nhoJ"//
+
+
+let reversedName = hacker2.split("").reverse().join("")
+console.log(reversedName)
+
+//3.3 Depending on the lexicographic order of the strings, print: - The driver's name goes first. - Yo, the navigator goes first definitely. - What?! You both got the same name?//
+
+let abc = "abcdefghijklmnopqrstuvwxyz";
+let firstLetterHacker1 = hacker1[0];
+let firstLetterHacker2 = hacker2[0];
+  if (abc.indexOf(firstLetterHacker1) < abc.indexOf(firstLetterHacker2)){
+    if(abc.indexOf(firstLetterHacker1) == abc.indexOf(firstLetterHacker2)){
+      console.log("Both have the same first letter");
+    } else {
+    console.log(`${hacker1} goes first`);
+    }
+  }
+    else{
+    console.log(`${hacker2} goes first`);
+  }
+
+/*Bonus Time!
+Go to lorem ipsum generator and:
+
+Generate 3 paragraphs. Store the text in a variable type of string.
+Make your program count the number of words in the string.
+Make your program count the number of times the Latin word et appears.*/
+//1.4 Print "The navigator's name is YYYY".//
+
+console.log(`The navigator´s name is ${hacker2}`);
+
+/*Iteration 2: Conditionals
+2.1. Depending on which name is longer, print: - The Driver has the longest name, it has XX characters or - Yo, navigator got the longest name, it has XX characters or - Wow, you both got equally long names, XX characters!*/
+
+if (hacker1.length >=hacker2.length){
+  if (hacker1.length == hacker2.length){
+    console.log(`Wow, you both got equally long names, ${hacker1.length} characters!`)
+  } else {
+    console.log(`The Driver has the longest name, it has ${hacker1.length} characters`)
+  } 
+} else {
+  console.log(`Yo, navigator got the longest name, it has ${hacker2.length} characters`)
+}
+
+/*Iteration 3: Loops
+3.1 Print all the characters of the driver's name, separated by a space and in capitals i.e. "J O H N"*/
+
 //3.2 Print all the characters of the navigator's name, in reverse order. i.e. "nhoJ"//
 
 //3.3 Depending on the lexicographic order of the strings, print: - The driver's name goes first. - Yo, the navigator goes first definitely. - What?! You both got the same name?//