diff --git a/.vscode/settings.json b/.vscode/settings.json
new file mode 100644
index 000000000..6f3a2913e
--- /dev/null
+++ b/.vscode/settings.json
@@ -0,0 +1,3 @@
+{
+    "liveServer.settings.port": 5501
+}
\ No newline at end of file
diff --git a/index.js b/index.js
index 6b0fec3ad..2ecf18138 100644
--- a/index.js
+++ b/index.js
@@ -1,7 +1,95 @@
 // Iteration 1: Names and Input
 
+//1.1 Create a variable hacker1 with the driver's name.
+
+    let hacker1 = "Nacho";
+
+//1.2 Print "The driver's name is XXXX".
+
+    console.log(`The driver's name is ${hacker1}`); 
+
+//1.3 Create a variable hacker2 with the navigator's name.
+
+    let hacker2 = "Laura"; 
+
+//1.4 Print "The navigator's name is YYYY".*/ 
+
+    console.log(`The navigator's name is ${hacker2}`); 
+
+
 
 // Iteration 2: Conditionals
+/*
+2.1. Depending on which name is longer, print:
+
+    - The driver has the longest name, it has XX characters. or
+
+    - It seems that the navigator has the longest name, it has XX characters. or
+    
+    - Wow, you both have equally long names, XX characters!. 
+
+*/
+
+if (hacker1.length > hacker2.length){
+
+    console.log(`The driver has the longest name, it has ${hacker1.length} characters`); 
+}
+else if {
+
+    console.log(`It seems that the navigator has the longest name, it has ${hacker2.length} characters`); 
+
+}
+else {
+
+    console.log(`Wow, you both have equally long names, XX characters!.`); 
+
+}
+
 
 
 // Iteration 3: Loops
+
+//3.1 Print the characters of the driver's name, separated by space, and in capital letters, i.e., "J O H N".
+
+console.log(hacker1.length) //Con esto sacamos la longitud del string en el caso de desconocerla.
+
+let hacker1NameCaptial = hacker1.toUpperCase(); // Pasamos todos los caracteres del nombre a mayúsculas.
+
+console.log(hacker1NameCaptial.substring(0,1)+" "+hacker1NameCaptial.substring(1,2)+" "+hacker1NameCaptial.substring(2,3)+" "+hacker1NameCaptial.substring(3,4)+" "+hacker1NameCaptial.substring(4)+" "); 
+
+// O también: 
+
+console.log(hacker1NameCaptial.slice(0,1)+" "+hacker1NameCaptial.slice(1,2)+" "+hacker1NameCaptial.slice(2,3)+" "+hacker1NameCaptial.slice(3,4)+" "+hacker1NameCaptial.slice(4)+" ");
+
+
+
+//3.2 Print all the characters of the navigator's name in reverse order, i.e., "nhoJ".
+
+console.log(hacker2.length); //Así averiguamos el número de caracteres del string.
+
+let reHacker2 = hacker2.split(''); //Con esto separo los caracteres del string.
+
+console.log(reHacker2[4]+reHacker2[3]+reHacker2[2]+reHacker2[1]+reHacker2[0]);
+ 
+/*
+3.3 Depending on the lexicographic order of the strings, print:
+
+- The driver's name goes first.
+
+- Yo, the navigator goes first, definitely.
+
+- What?! You both have the same name?
+
+*/
+
+if (hacker1.charCodeAt(hacker1[0]) < hacker2.charCodeAt(hacker2[0])) {
+  
+    console.log("The driver's name goes first.")
+    
+  }
+  else if (hacker1.charCodeAt(hacker1[0]) > hacker2.charCodeAt(hacker2[0])) {
+    
+    console.log("Yo, the navigator goes first, definitely.")
+    
+  }
+   else {(console.log("What?! You both have the same name?"));}
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