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maximum-subarray.py
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56 lines (46 loc) · 1.34 KB
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# -*- coding: utf-8 -*-
"""
Given an integer array nums, find the contiguous subarray (containing at least one number)
which has the largest sum and return its sum.
Example:
Input: [-2,1,-3,4,-1,2,1,-5,4],
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.
Follow up:
If you have figured out the O(n) solution, try coding another solution
using the divide and conquer approach, which is more subtle.
"""
class Solution:
def maxSubArray(self, nums):
"""
:type nums: List[int]
:rtype: int
>>> s = Solution()
>>> nums = [-2,1,-3,4,-1,2,1,-5,4]
>>> s.maxSubArray(nums)
6
>>> nums1 = [-2,-1]
>>> s.maxSubArray(nums1)
-1
>>> nums2 = [2,1]
>>> s.maxSubArray(nums2)
3
Explanation: [4,-1,2,1] has the largest sum = 6.
"""
# leetcode一个人的犀利解法。服气
# for i in range(1, len(nums)):
# if nums[i-1] > 0:
# nums[i] += nums[i-1]
# return max(nums)
l = len(nums)
if l == 1:
return nums[0]
sum_ = nums[0]
max_ = nums[0]
for i in range(1, l):
sum_ = max(nums[i], sum_ + nums[i])
max_ = max(sum_, max_)
return max_
if __name__ == '__main__':
import doctest
doctest.testmod(verbose=True)