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array-partition-I.py
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44 lines (35 loc) · 1.05 KB
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# -*- coding: utf-8 -*-
"""
Given an array of 2n integers, your task is to group these integers into n pairs of integer,
say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.
Example 1:
Input: [1,4,3,2]
Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).
Note:
n is a positive integer, which is in the range of [1, 10000].
All the integers in the array will be in the range of [-10000, 10000].
"""
class Solution:
def arrayPairSum(self, nums):
"""
:type nums: List[int]
:rtype: int
>>> test1 = [1,4,3,2]
>>> s = Solution()
>>> s.arrayPairSum(test1)
4
"""
# 排序然后隔一取值
l = len(nums)
nums.sort()
sum_ = 0
if l == 2:
return min(nums)
for i in range(0, l, 2):
sum_ += nums[i]
return sum_
# return sum(sorted(nums)[::2])
if __name__ == '__main__':
import doctest
doctest.testmod(verbose=True)