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UriPage may produce invalid URIs #428

Description

@ostumpf

When such URI is presented to the constructor of UriPage:
new UriPage("uri?test=foo%20bar");
and the UriPage is then serialized back to URI:
uri.getPageUri(null).toString();
the result is "uri?test=foo%2520bar" instead of "uri?test=foo%20bar", because the percent sign is escaped.

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