forked from wuduhren/leetcode-python
-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathbinary-search-tree-iterator.py
More file actions
64 lines (46 loc) · 1.24 KB
/
binary-search-tree-iterator.py
File metadata and controls
64 lines (46 loc) · 1.24 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
class BSTIterator(object):
def __init__(self, root):
self.stack = []
while root:
self.stack.append(root)
root = root.left
def next(self):
node = self.stack.pop()
r = node.right
while r:
self.stack.append(r)
r = r.left
return node.val
def hasNext(self):
return len(self.stack)!=0
"""
Time: init() O(1). next() O(LogN). hasNext() O(1).
Space: O(N)
"""
class BSTIterator(object):
def __init__(self, root):
self.node = root
self.stack = []
def next(self):
while self.node:
self.stack.append(self.node)
self.node = self.node.left
node = self.stack.pop()
self.node = node.right
return node.val
def hasNext(self):
return self.stack or self.node
"""
FYI. Template for in-order traverse.
"""
def inOrderTraverse(root):
stack = []
node = root
while node or stack:
while node:
stack.append(node)
node = node.left
node = stack.pop()
#do something
print node.val
node = node.right