Given an array of even and odd numbers, return an array of even, convert odd numbers to even.

• Input: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10], Output: [2, 2, 4, 4, 6, 6, 8, 8, 10, 10]
• Input: [1, 3, 5, 7, 9], Output: [2, 4, 6, 8, 10]
• Input: [2, 4, 6, 8, 10], Output: [2, 4, 6, 8, 10]

const numbers = [12, 43, 11, 77, 60, 40, 45];

const oddToEven = arr => {
    const evenArr = arr.map(ele => {
        return ele % 2 !== 0 ? ele + 1 : ele
    })
    return evenArr;
}
oddToEven(numbers);

• The function takes an array as a parameter.
• It creates a variable called evenArr and assigns it a value of the array passed as a parameter.
• Using the map method, it iterates through the array and checks if the element is odd or even.
• If the element is odd, it adds 1 to it and returns it.
• If the element is even, it returns it.
• It returns the evenArr variable.

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Pull requests are welcome. For major changes, please open an issue first to discuss what you would like to change.

Please make sure to update tests as appropriate.