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Solution429.java
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48 lines (43 loc) · 1.35 KB
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import java.util.*;
public class Solution429 {
/**
* N叉树的层序遍历
* 利用队列,在左边添加,在右边消费,右边每消费一个节点,便将其的children-node添加到左边,考虑到读取的顺序,按children的顺序添加即可
*
* @param root 根节点
* @return 遍历结果
*/
public List<List<Integer>> levelOrder(Node root) {
if (root == null) {
return new LinkedList<>();
}
Queue<Node> queue = new LinkedList<>();
List<List<Integer>> result = new LinkedList<>();
queue.add(root);
while (!queue.isEmpty()) {
List<Integer> list = new LinkedList<>();
// 每次清空当前queue中内容,及该层全部内容
int queueSize = queue.size();
for (int i = 0; i < queueSize; i++) {
Node node = queue.poll();
list.add(node.val);
queue.addAll(node.children);
}
result.add(list);
}
return result;
}
class Node {
public int val;
public List<Node> children;
public Node() {
}
public Node(int _val) {
val = _val;
}
public Node(int _val, List<Node> _children) {
val = _val;
children = _children;
}
}
}