Given a weighted, undirected and connected graph of V vertices and an adjacency list adj where adj[i] is a list of lists containing two integers where the first integer of each list j denotes there is edge between i and j , second integers corresponds to the weight of that edge .
You are given the source vertex S and You to Find the shortest distance of all the vertex's from the source vertex S.
You have to return a list of integers denoting shortest distance between each node and Source vertex S.
Note: The Graph doesn't contain any negative weight cycle.
Input:
V = 2
adj [] = {{{1, 9}}, {{0, 9}}}
S = 0
Output: [0 9]
Explanation:
The source vertex is 0. Hence, the shortest
distance of node 0 is 0 and the shortest
distance from node 1 is 9.
Input:
V = 3, E = 3
adj = {{{1, 1}, {2, 6}}, {{2, 3}, {0, 1}}, {{1, 3}, {0, 6}}}
S = 2
Output: [4 3 0]
Explanation:
For nodes 2 to 0, we can follow the path-
2-1-0. This has a distance of 1+3 = 4,
whereas the path 2-0 has a distance of 6. So,
the Shortest path from 2 to 0 is 4.
The shortest distance from 0 to 1 is 1 .
- 1 ≤ V ≤ 1000
- 0 ≤ adj[i][j] ≤ 1000
- 1 ≤ adj.size() ≤ [ (V*(V - 1)) / 2 ]
- 0 ≤ S < V