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docs/standard-library/algorithm-functions.md

Lines changed: 29 additions & 19 deletions
Original file line numberDiff line numberDiff line change
@@ -2270,23 +2270,23 @@ The complexity is linear with at most *`count`* operations.
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```cpp
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// alg_for_each_n.cpp
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// compile with: /EHsc
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#include <vector>
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#include <algorithm>
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#include <iostream>
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#include <vector>
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// The function object multiplies an element by a Factor
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template <class Type>
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class MultValue
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template <class Type> class MultValue
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{
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private:
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Type Factor; // The value to multiply by
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public:
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private:
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Type Factor; // The value to multiply by
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public:
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// Constructor initializes the value to multiply by
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MultValue ( const Type& value ) : Factor ( value ) {
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MultValue(const Type &value) : Factor(value)
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{
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}
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// The function call for the element to be multiplied
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void operator( ) ( Type& elem ) const
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void operator()(Type &elem) const
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{
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elem *= Factor;
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}
@@ -2299,36 +2299,46 @@ int main()
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vector<int>::iterator Iter;
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// Constructing vector v
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int i;
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for ( i = -4 ; i <= 2 ; i++ )
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for (int i = -4; i <= 2; i++)
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{
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v.push_back( i );
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v.push_back(i);
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}
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cout << "Original vector v = ( " ;
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for ( Iter = v.begin( ) ; Iter != v.end( ) ; Iter++ )
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cout << "Original vector v = ( ";
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for (Iter = v.begin(); Iter != v.end(); Iter++)
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{
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cout << *Iter << " ";
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}
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cout << ")." << endl;
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// Using for_each_n to multiply the first 3 elements by a Factor,
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// saving position
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auto pos = for_each_n ( v.begin( ), 3, MultValue<int> ( -2 ) );
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auto pos = for_each_n(v.begin(), 3, MultValue<int>(-2));
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cout << "Multiplying the first 3 elements of the vector v\n "
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<< "by the factor -2 gives:\n vmod1 = ( " ;
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for ( Iter = v.begin( ) ; Iter != v.end( ) ; Iter++ )
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<< "by the factor -2 gives:\n vmod1 = ( ";
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for (Iter = v.begin(); Iter != v.end(); Iter++)
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{
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cout << *Iter << " ";
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}
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cout << ")." << endl;
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// Using for_each_n to multiply the next 3 elements by a Factor,
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// starting at the position saved by the previous for_each_n
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for_each_n ( pos, 4, MultValue<int> ( -3 ) );
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for_each_n(pos, 4, MultValue<int>(-3));
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cout << "Multiplying the next 4 elements of the vector v\n "
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<< "by the factor -3 gives:\n vmod2 = ( " ;
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for ( Iter = v.begin( ) ; Iter != v.end( ) ; Iter++ )
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<< "by the factor -3 gives:\n vmod2 = ( ";
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for (Iter = v.begin(); Iter != v.end(); Iter++)
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{
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cout << *Iter << " ";
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}
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cout << ")." << endl;
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return 0;
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}
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```
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