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| 1 | +// 16. Check if String is Palindrome |
| 2 | + |
| 3 | +// Method 1: Naive Approach |
| 4 | + |
| 5 | +{ |
| 6 | + function check_palindrome(str) { |
| 7 | + let j = str.length - 1; |
| 8 | + for (let i = 0; i < j / 2; i++) { |
| 9 | + let x = str[i]; |
| 10 | + let y = str[j - i]; |
| 11 | + |
| 12 | + if (x != y) { |
| 13 | + return false; |
| 14 | + } |
| 15 | + } |
| 16 | + return true; |
| 17 | + } |
| 18 | + |
| 19 | + function isPalindrome(str) { |
| 20 | + let ans = check_palindrome(str); |
| 21 | + |
| 22 | + if (ans == true) console.log(str + " is a palindrome"); |
| 23 | + else console.log(str + " not palindrome"); |
| 24 | + } |
| 25 | + |
| 26 | + let test = "abaaba"; |
| 27 | + isPalindrome(test); |
| 28 | + |
| 29 | + console.log(check_palindrome("jalaj")); |
| 30 | +} |
| 31 | + |
| 32 | +// Method 2: Reversing the string |
| 33 | + |
| 34 | +{ |
| 35 | + function reverse(str) { |
| 36 | + let rev_str = ""; |
| 37 | + for (let i = str.length - 1; i >= 0; i--) { |
| 38 | + rev_str += str[i]; |
| 39 | + } |
| 40 | + |
| 41 | + return rev_str; |
| 42 | + } |
| 43 | + |
| 44 | + function isPalindrome(str) { |
| 45 | + reverse_str = reverse(str); |
| 46 | + |
| 47 | + if (reverse_str === str) { |
| 48 | + console.log("passed string is palindrome"); |
| 49 | + } else { |
| 50 | + console.log("passed string is not palindrome"); |
| 51 | + } |
| 52 | + } |
| 53 | + |
| 54 | + let test = "hellolleh"; |
| 55 | + isPalindrome(test); |
| 56 | +} |
| 57 | + |
| 58 | +// Method 3: Using the split(), reverse(), and join() Methods |
| 59 | + |
| 60 | +{ |
| 61 | + let check_palindrome = (str) => str === str.split("").reverse().join(""); |
| 62 | + console.log(check_palindrome("hellolleh")); |
| 63 | +} |
| 64 | + |
| 65 | +// Method 4: Using Array.every() |
| 66 | + |
| 67 | +{ |
| 68 | + function isPalindrome(str) { |
| 69 | + return str |
| 70 | + .split("") |
| 71 | + .every((char, index) => char === str[str.length - index - 1]); |
| 72 | + } |
| 73 | + |
| 74 | + console.log(isPalindrome("radar")); |
| 75 | + console.log(isPalindrome("hello")); |
| 76 | + console.log(isPalindrome("level")); |
| 77 | +} |
| 78 | + |
| 79 | +// Method 5: Using Two Pointers |
| 80 | + |
| 81 | +{ |
| 82 | + function isPalindrome(str) { |
| 83 | + let left = 0; |
| 84 | + let right = str.length - 1; |
| 85 | + |
| 86 | + while (left < right) { |
| 87 | + if (str[left] !== str[right]) return false; |
| 88 | + |
| 89 | + left++; |
| 90 | + right--; |
| 91 | + } |
| 92 | + |
| 93 | + return true; |
| 94 | + } |
| 95 | + |
| 96 | + console.log(isPalindrome("madam")); |
| 97 | + console.log(isPalindrome("test")); |
| 98 | + console.log(isPalindrome("abba")); |
| 99 | +} |
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