// Program to check whether a number is an armstrong number or not

#include <cmath>

#include <iostream>

using std::cin;

using std::cout;

int main() {

int n = 0, temp = 0, rem = 0, count = 0, sum = 0;

cout << "Enter a number: ";

cin >> n;

temp = n;

/* First Count the number of digits

in the given number */

while (temp != 0) {

temp /= 10;

count++;

}

/* Calculation for checking of armstrongs number i.e.

in an n-digit number sum of the digits is raised to a power of n

is equal to the original number */

temp = n;

while (temp != 0) {

rem = temp % 10;

sum += static_cast<int>(pow(rem, count));

temp /= 10;

}

if (sum == n) {

cout << n << " is an armstrong number";

} else {

cout << n << " is not an armstrong number";

}

return 0;

}