# https://leetcode.com/problems/compare-version-numbers/

# Runtime: 28 ms, faster than 80.32% of Python3 online submissions for Compare Version Numbers.

# Memory Usage: 14.2 MB, less than 60.47% of Python3 online submissions for Compare Version Numbers.

class Solution:

def compareVersion(self, version1: str, version2: str) -> int:

v1, v2 = version1.split('.'), version2.split('.')

while v1 or v2:

rev1 = v1.pop(0) if v1 else None

rev2 = v2.pop(0) if v2 else None

if not rev1 and rev2:

if int(rev2) == 0:

continue

else:

return -1

elif rev1 and not rev2:

if int(rev1) == 0:

continue

else:

return 1

elif int(rev1) < int(rev2):

return -1

elif int(rev1) > int(rev2):

return 1

else:

continue

return 0

if __name__ == '__main__':

print(Solution().compareVersion(version1="1.01", version2="1.001"))

print(Solution().compareVersion(version1="1.0", version2="1.0.0"))

print(Solution().compareVersion(version1="0.1", version2="1.1"))

print(Solution().compareVersion(version1="1.0.1", version2="1"))

print(Solution().compareVersion(version1="7.5.2.4", version2="7.5.3"))