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README.md

Given an array of integers A with even length, return true if and only if it is possible to reorder it such that A[2 * i + 1] = 2 * A[2 * i] for every 0 <= i < len(A) / 2.

 

Example 1:

Input: [3,1,3,6]
Output: false

Example 2:

Input: [2,1,2,6]
Output: false

Example 3:

Input: [4,-2,2,-4]
Output: true
Explanation: We can take two groups, [-2,-4] and [2,4] to form [-2,-4,2,4] or [2,4,-2,-4].

Example 4:

Input: [1,2,4,16,8,4]
Output: false

 

Note:

  1. 0 <= A.length <= 30000
  2. A.length is even
  3. -100000 <= A[i] <= 100000

Companies:
Google

Related Topics:
Array, Hash Table

Solution 1. Greedy

// OJ: https://leetcode.com/problems/array-of-doubled-pairs/
// Author: github.com/lzl124631x
// Time: O(NlogN)
// Space: O(N)
class Solution {
public:
    bool canReorderDoubled(vector<int>& A) {
        multiset<int> s(A.begin(), A.end());
        while (s.size()) {
            int val = *s.begin();
            if (val < 0 && val % 2) return false;
            int next = val >= 0 ? val * 2 : val / 2;
            s.erase(s.begin());
            auto it = s.find(next);
            if (it == s.end()) return false;
            s.erase(it);
        }
        return true;
    }
};