A query word matches a given pattern if we can insert lowercase letters to the pattern word so that it equals the query. (We may insert each character at any position, and may insert 0 characters.)

Given a list of queries, and a pattern, return an answer list of booleans, where answer[i] is true if and only if queries[i] matches the pattern.

Example 1:

Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FB"
Output: [true,false,true,true,false]
Explanation: 
"FooBar" can be generated like this "F" + "oo" + "B" + "ar".
"FootBall" can be generated like this "F" + "oot" + "B" + "all".
"FrameBuffer" can be generated like this "F" + "rame" + "B" + "uffer".

Example 2:

Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBa"
Output: [true,false,true,false,false]
Explanation: 
"FooBar" can be generated like this "Fo" + "o" + "Ba" + "r".
"FootBall" can be generated like this "Fo" + "ot" + "Ba" + "ll".

Example 3:

Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBaT"
Output: [false,true,false,false,false]
Explanation: 
"FooBarTest" can be generated like this "Fo" + "o" + "Ba" + "r" + "T" + "est".

Note:

1. 1 <= queries.length <= 100
2. 1 <= queries[i].length <= 100
3. 1 <= pattern.length <= 100
4. All strings consists only of lower and upper case English letters.

Related Topics:
String, Trie

// OJ: https://leetcode.com/problems/camelcase-matching/
// Author: github.com/lzl124631x
// Time: O(QP)
// Space: O(1)
class Solution {
    bool match(string &s, string &p) {
        int i = 0, N = p.size();
        for (char c : s) {
            if (i == N) {
                if (isupper(c)) return false;
            } else if (isupper(p[i])) {
                if (islower(c)) continue;
                if (c != p[i++]) return false;
            } else if (c != p[i]) continue;
            else ++i;
        }
        return i == N;
    }
public:
    vector<bool> camelMatch(vector<string>& queries, string pattern) {
        vector<bool> ans;
        for (auto &s : queries) ans.push_back(match(s, pattern));
        return ans;
    }
};