From 300eca70a86ae47cf421c9c83d0e1069452f2509 Mon Sep 17 00:00:00 2001
From: NovaGod <73330194+NovaGod@users.noreply.github.com>
Date: Fri, 23 Oct 2020 12:14:29 +0530
Subject: [PATCH] EVEN or ODD

We can check whether an integer number is EVEN or ODD without using any Arithmetic or Relational operators.

Here is a simple trick that we can use to check whether number is EVEN or ODD. Using Logical AND (&) operator we can check it, each EVEN number has 0th bit LOW (0) and ODD number has 0th bit HIGH (1).

The statement (number & 0x01) will check that 0th bit is HIGH, if it is HIGH (1) number will be an ODD otherwise number will be an EVEN.
---
 EVEN or ODD | 16 ++++++++++++++++
 1 file changed, 16 insertions(+)
 create mode 100644 EVEN or ODD

diff --git a/EVEN or ODD b/EVEN or ODD
new file mode 100644
index 00000000..9ee48036
--- /dev/null
+++ b/EVEN or ODD	
@@ -0,0 +1,16 @@
+#include <stdio.h>
+ 
+int main()
+{
+    int number;
+     
+    //input an integer number
+    printf("Please input an integer number: ");
+    scanf("%d",&number);
+         
+    //check 0th bit of number is 1 or 0
+    (number & 0x01) ? printf("%d is an ODD Number.", number) :  printf("%d is an EVEN Number.",number) ;
+     
+    printf("\n");
+    return 0;   
+}