Determine the day of the year.
var dayOfYear = require( '@stdlib/time/day-of-year' );Returns the day of the year.
var num = dayOfYear();
// returns <number>By default, the function returns the day of the year for the current date (according to local time). To determine the day of the year for a particular day, provide month, day, and year arguments.
var num = dayOfYear( 12, 31, 2016 );
// returns 366
num = dayOfYear( 12, 31, 2017 );
// returns 365A month may be either a month's integer value, three letter abbreviation, or full name (case insensitive).
var num = dayOfYear( 12, 31, 2016 );
// returns 366
num = dayOfYear( 'dec', 31, 2016 );
// returns 366
num = dayOfYear( 'december', 31, 2016 );
// returns 366The function also supports providing a Date object.
var num = dayOfYear( new Date() );
// returns <number>var dayOfYear = require( '@stdlib/time/day-of-year' );
var v;
var i;
for ( i = 0; i < 2021; i++ ) {
v = dayOfYear( 'Dec', 31, i );
console.log( 'In the year %d, December 31 is day number %d.', i, v );
}Usage: day-of-year [options] [<month> <day> <year>]
Options:
-h, --help Print this message.
-V, --version Print the package version.
$ day-of-year
<number>For a specific date,
$ day-of-year 12 31 2016
366@stdlib/time/day-of-quarter: determine the day of the quarter.