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src/sequences/longest_increasing_subsequence.md
@@ -200,7 +200,7 @@ And again we have to create an array of "ancestors" $p[i]$.
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$p[i]$ will be the index of the previous element for the optimal subsequence ending in element $i$.
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It's easy to maintain these two arrays in the course of iteration over the array $a[]$ alongside the computations of $d[]$.
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-And at the end it in not difficult to restore the desired subsequence using these arrays.
+And at the end it is not difficult to restore the desired subsequence using these arrays.
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## Solution in $O(n \log n)$ with data structures
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