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reverseBits.java
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45 lines (44 loc) · 1.1 KB
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public class Solution {
// you need treat n as an unsigned value
public int reverseBits(int n) {
int result =0;
for(int i=0;i<32;i++)
{
result+=n&1;
n>>=1;
if(i<31)
result<<=1;
}
return result;
}
}
-------------------------------------
// this is a optimization
// cache
private final Map<Byte, Integer> cache = new HashMap<Byte, Integer>();
public int reverseBits(int n) {
byte[] bytes = new byte[4];
for (int i = 0; i < 4; i++) // convert int into 4 bytes
bytes[i] = (byte)((n >>> 8*i) & 0xFF);
int result = 0;
for (int i = 0; i < 4; i++) {
result += reverseByte(bytes[i]); // reverse per byte
if (i < 3)
result <<= 8;
}
return result;
}
private int reverseByte(byte b) {
Integer value = cache.get(b); // first look up from cache
if (value != null)
return value;
value = 0;
// reverse by bit
for (int i = 0; i < 8; i++) {
value += ((b >>> i) & 1);
if (i < 7)
value <<= 1;
}
cache.put(b, value);
return value;
}