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99 lines (90 loc) · 2.48 KB
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package DP;
import Entitys.TreeNode;
import org.junit.Test;
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Queue;
/**
* @author dekai.kong
* @difficult Medium
* @create 2020-08-01 20:45
* @from
**/
public class RobIII {
public RobIII() {
}
/**
* 层序遍历 此解法不对,因为 不能选跨层的,所以要使用后续遍历
*/
List<List<Integer>> level = new ArrayList();
public int rob(TreeNode root) {
if (root == null) {
return 0;
}
Queue<TreeNode> q = new LinkedList<>();
q.offer(root);
while (!q.isEmpty()) {
List<Integer> list = new ArrayList<>();
for (int i = q.size(); i > 0; i--) {
TreeNode tn = q.poll();
list.add(tn.val);
if (tn.left != null) {
q.offer(tn.left);
}
if (tn.right != null) {
q.offer(tn.right);
}
}
level.add(new ArrayList(list));
}
int[] dp = new int[level.size()];
dp[0] = level.get(0).get(0);
if(level.size() == 1){
return dp[0];
}
int lv1 = 0;
for (int i = 0; i < level.get(1).size(); i++) {
lv1 += level.get(1).get(i);
}
dp[1] = Math.max(dp[0], lv1);
for (int i = 2; i < level.size(); i++) {
int lvi = 0;
for (int j = 0; j < level.get(i).size(); j++) {
lvi += level.get(i).get(j);
}
dp[i] = Math.max(dp[i - 1], dp[i - 2] + lvi);
}
return dp[level.size() - 1];
}
/**
* 0ms 100%
* @param root
* @return
*/
public int rob2(TreeNode root){
if(root == null){
return 0;
}
int[] ans = helper(root);
return Math.max(ans[0],ans[1]);
}
public int[] helper(TreeNode root){
if(root == null){
return new int[2];
}
int[] left = helper(root.left);
int[] right = helper(root.right);
int[] dp = new int[2];
//不选根 选子节点的子节点里最大的
dp[0] = Math.max(left[0],left[1])+ Math.max(right[0],right[1]);
//选根 肯定选子节点的子节点
dp[1] = root.val + left[0]+right[0];
return dp;
}
@Test
public void test() {
TreeNode tn = TreeNode.genTreeNode(new int[]{1},0);
rob2(tn);
}
}