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Solution.rb
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82 lines (52 loc) · 1.23 KB
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# Definition for a binary tree node.
class TreeNode
attr_accessor :val, :left, :right
def initialize(val)
@val = val
@left, @right = nil, nil
end
end
# @param {TreeNode} root
# @return {Integer[][]}
def level_order_bottom(root)
if root.nil?
return []
end
if root.left.nil? and root.right.nil?
return [[root.val]]
end
treeQueue = Array.new
treeQueue << root
treeQueue << '#'
index = 0
matrix = []
vector = Array.new
while index < treeQueue.size
# print "#{treeQueue}\n"
if treeQueue[index].class == '#'.class
if (index + 1 < treeQueue.size)
treeQueue << '#'
end
matrix << vector
vector = Array.new
else
vector << treeQueue[index].val
unless treeQueue[index].left.nil?
treeQueue << treeQueue[index].left
end
unless treeQueue[index].right.nil?
treeQueue << treeQueue[index].right
end
end
index += 1
end
matrix.reverse
end
root = TreeNode.new(1)
root.left = TreeNode.new(2)
root.right = TreeNode.new(3)
root.left.left = TreeNode.new(4)
# root.left.left.right = TreeNode.new(5)
root.right.left = TreeNode.new(4)
# root.right.right = TreeNode.new(5)
print level_order root