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Sort0toN3.java
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45 lines (36 loc) · 1.07 KB
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package com.interview.sort;
/**
* http://www.geeksforgeeks.org/sort-n-numbers-range-0-n2-1-linear-time/
*/
public class Sort0toN3 {
public void sort(int arr[],int n){
sort(arr,n,1);
sort(arr,n,n);
sort(arr,n,n*n);
}
private void sort(int arr[],int n, int exp){
int count[] = new int[n];
for(int i=0; i < arr.length;i++){
count[(arr[i]/exp)%n]++;
}
for(int i=1; i < arr.length; i++){
count[i] += count[i-1];
}
int output[] = new int[n];
for(int i=arr.length-1;i>=0; i--){
output[count[(arr[i]/exp)%n]-1] = arr[i];
count[(arr[i]/exp)%n]--;
}
for(int i=0; i < arr.length; i++){
arr[i] = output[i];
}
}
public static void main(String args[]){
int arr[] = {100,2,124,18,36};
Sort0toN3 sn = new Sort0toN3();
sn.sort(arr,arr.length);
for(int i=0; i < arr.length; i++){
System.out.print(arr[i] + " ");
}
}
}